2c^2=3200

Solution for 2c^2=3200 equation:

2c^2=3200

We move all terms to the left:

2c^2-(3200)=0

a = 2; b = 0; c = -3200;
Δ = b2-4ac
Δ = 02-4·2·(-3200)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-160}{2*2}=\frac{-160}{4}
=-40
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+160}{2*2}=\frac{160}{4}
=40
$